comment_law_12

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Both sides previous revision Προηγούμενη αναθεώρηση
comment_law_12 [2019/03/05 12:13]
pournaras
comment_law_12 [2019/03/05 12:17] (τρέχουσα)
pournaras
Γραμμή 267: Γραμμή 267:
 Example 11: Example 11:
  
-A pair is misinformed and ends up in 3NT going down one instead of playing in a making 6♦contract. If the polling shows that it is easy to get to 6♦with correct information,​ then the TDshould assign 100% of 6♦.+A pair is misinformed and ends up in 3NT going down one instead of playing in a making 6♦ contract. If the polling shows that it is easy to get to 6♦ with correct information,​ then the TD should assign 100% of 6♦.
  
-If however the polling shows only a ~50% chance of the pair getting to 6♦, then the TD should assign a percentage of 6♦making together with a proportion of the various (successful and nonsuccessful) game-level contracts. After factoring in the associated uncertainty the TD obtains an adjusted frequency of: 0.50 x 1.2 = 0.60 (which equates to 6♦making ~60% of the time).+If however the polling shows only a ~50% chance of the pair getting to 6♦, then the TD should assign a percentage of 6♦ making together with a proportion of the various (successful and nonsuccessful) game-level contracts. After factoring in the associated uncertainty the TD obtains an adjusted frequency of: 0.50 x 1.2 = 0.60 (which equates to 6♦ making ~60% of the time).
  
-Now let us suppose that for 6♦to make the declarer has to find a queen and it is a pure guess. We therefore don’t know if he would get it right or not, so it is now normal to include a proportion of both 6♦making and 6♦going down as part of the final weighted result (again giving some consideration to the margin of doubt associated with the process). Hence, if it seems that getting to 6♦is 100% certain and making it is only a ~50% chance; the assigned score would be 6♦making ~60% of the time (0.50 x 1.2 = 0.60) and going down ~40% of the time.+Now let us suppose that for 6♦ to make the declarer has to find a queen and it is a pure guess. We therefore don’t know if he would get it right or not, so it is now normal to include a proportion of both 6♦ making and 6♦ going down as part of the final weighted result (again giving some consideration to the margin of doubt associated with the process). Hence, if it seems that getting to 6♦ is 100% certain and making it is only a ~50% chance; the assigned score would be 6♦ making ~60% of the time (0.50 x 1.2 = 0.60) and going down ~40% of the time.
  
-If the TD discovers that only ~50% of the players polled would get to 6♦, and that those in 6♦would only make it ~50% of the time then, based upon the raw percentages,​ we would expect thenon-offenders to get the score for 6♦making ~25% of the time. But since they are the non-offendingside, it is entirely appropriate to give them some benefit of doubt and assign 6♦making ~30% of the time (0.25 x 1.2 = 0.30). This means that the remaining ~70% would need toinclude those occasions when 6♦fails, as well some proportion of 5♦making and 3NT failing.+If the TD discovers that only ~50% of the players polled would get to 6♦, and that those in 6♦ would only make it ~50% of the time then, based upon the raw percentages,​ we would expect the non-offenders to get the score for 6♦ making ~25% of the time. But since they are the non-offending side, it is entirely appropriate to give them some benefit of doubt and assign 6♦ making ~30% of the time (0.25 x 1.2 = 0.30). This means that the remaining ~70% would need to include those occasions when 6♦ fails, as well some proportion of 5♦ making and 3NT failing.
  
 === Serious error === === Serious error ===
  • comment_law_12.txt
  • Τελευταία τροποποίηση: 2019/03/05 12:17
  • από pournaras